(5x^2+41x+8)(x-4)=0

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Solution for (5x^2+41x+8)(x-4)=0 equation: 


Simplifying
(5x2 + 41x + 8)(x + -4) = 0

Reorder the terms:
(8 + 41x + 5x2)(x + -4) = 0

Reorder the terms:
(8 + 41x + 5x2)(-4 + x) = 0

Multiply (8 + 41x + 5x2) * (-4 + x)
(8(-4 + x) + 41x * (-4 + x) + 5x2 * (-4 + x)) = 0
((-4 * 8 + x * 8) + 41x * (-4 + x) + 5x2 * (-4 + x)) = 0
((-32 + 8x) + 41x * (-4 + x) + 5x2 * (-4 + x)) = 0
(-32 + 8x + (-4 * 41x + x * 41x) + 5x2 * (-4 + x)) = 0
(-32 + 8x + (-164x + 41x2) + 5x2 * (-4 + x)) = 0
(-32 + 8x + -164x + 41x2 + (-4 * 5x2 + x * 5x2)) = 0
(-32 + 8x + -164x + 41x2 + (-20x2 + 5x3)) = 0

Combine like terms: 8x + -164x = -156x
(-32 + -156x + 41x2 + -20x2 + 5x3) = 0

Combine like terms: 41x2 + -20x2 = 21x2
(-32 + -156x + 21x2 + 5x3) = 0

Solving
-32 + -156x + 21x2 + 5x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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